Kunena 6.2.4 Released

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Question count module condition inside function

11 years 6 months ago - 11 years 6 months ago #1 by raryan
I am using this code in my joomla template for module block genaration,
this code call for below function;

module("top-col-", "1,2,3")

function module( $prefix, $comma_seperated_suffixes ) {
foreach( (array)explode( ",", $comma_seperated_suffixes ) as $suffix ) {
$module_name = $prefix.trim($suffix);
module_block( $module_name );

function module_block($jdoc_name) {
if(count(JModuleHelper::getModules($jdoc_name))) {
//this will hide this block if it is not active
<div id="<?php echo $jdoc_name; ?>" class="columns">
<jdoc:include type="modules" name="<?php echo $jdoc_name; ?>" style="html5" />

I want below code to insert into the function, but where. My mind not working. I am giving the example code below:

$module_name_block = (int)(count(JModuleHelper::getModules($jdoc_name)) > 0);

the above code will check for the published modules by taking module name from function, and then
count modules and get a class:

$CountModules = get all module here
if ($CountModules) : $Class = 'count-' . $CountModules;

automatically see which modules are published and count how many. this code must be inside my function
Last edit: 11 years 6 months ago by raryan.

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